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# Copyright 2023 VyOS maintainers and contributors <maintainers@vyos.io>
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library. If not, see <http://www.gnu.org/licenses/>.
def print_error(str='', end='\n'):
"""
Print `str` to stderr, terminated with `end`.
Used for warnings and out-of-band messages to avoid mangling precious
stdout output.
"""
import sys
sys.stderr.write(str)
sys.stderr.write(end)
sys.stderr.flush()
def ask_input(question, default='', numeric_only=False, valid_responses=[]):
question_out = question
if default:
question_out += f' (Default: {default})'
response = ''
while True:
response = input(question_out + ' ').strip()
if not response and default:
return default
if numeric_only:
if not response.isnumeric():
print("Invalid value, try again.")
continue
response = int(response)
if valid_responses and response not in valid_responses:
print("Invalid value, try again.")
continue
break
return response
def ask_yes_no(question, default=False) -> bool:
"""Ask a yes/no question via input() and return their answer."""
from sys import stdout
default_msg = "[Y/n]" if default else "[y/N]"
while True:
try:
stdout.write("%s %s " % (question, default_msg))
c = input().lower()
if c == '':
return default
elif c in ("y", "ye", "yes"):
return True
elif c in ("n", "no"):
return False
else:
stdout.write("Please respond with yes/y or no/n\n")
except EOFError:
stdout.write("\nPlease respond with yes/y or no/n\n")
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