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#!/usr/bin/env python3
#
# Copyright (C) 2020 VyOS maintainers and contributors
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License version 2 or later as
# published by the Free Software Foundation.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program. If not, see <http://www.gnu.org/licenses/>.
import re
from sys import argv,exit
if __name__ == '__main__':
if len(argv) != 2:
exit(1)
input = argv[1]
try:
# IP protocol can be in the range 0 - 255, thus the range must end with 256
if int(input) in range(0, 256):
exit(0)
except ValueError:
pass
pattern = "!?\\b(all|ip|hopopt|icmp|igmp|ggp|ipencap|st|tcp|egp|igp|pup|udp|" \
"tcp_udp|hmp|xns-idp|rdp|iso-tp4|dccp|xtp|ddp|idpr-cmtp|ipv6|" \
"ipv6-route|ipv6-frag|idrp|rsvp|gre|esp|ah|skip|ipv6-icmp|icmpv6|" \
"ipv6-nonxt|ipv6-opts|rspf|vmtp|eigrp|ospf|ax.25|ipip|etherip|" \
"encap|99|pim|ipcomp|vrrp|l2tp|isis|sctp|fc|mobility-header|" \
"udplite|mpls-in-ip|manet|hip|shim6|wesp|rohc)\\b"
if re.match(pattern, input):
exit(0)
print(f'Error: {input} is not a valid IP protocol')
exit(1)
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