Replace 'which' with 'command -v' to test for the existance of an executable

This is considered to be more robust.

Two instances remain:

scripts/build/chroot_archives, line 257:
if [ "${LB_APT}" = "aptitude" ] && [ ! $(Chroot chroot "which aptitude") ]
The command is run inside a chroot where the environment might be special,
and would need further testing.

manpages/Makefile, line 42:
@if [ ! -x "$$(which po4a 2>/dev/null)" ]; \
I am insufficiently familiar with makefile syntax to edit this.

1 files changed, 1 insertions, 1 deletions

diff --git a/frontend/live-build b/frontend/live-build
index 29efec9cf..2980158c0 100755
--- a/frontend/live-build
+++ b/frontend/live-build
@@ -23,7 +23,7 @@
 
 set -e
 
-if [ $(which man) ]
+if command -v man >/dev/null
 then
 	man live-build
 else