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#Newsgroups: comp.unix.admin,comp.unix.solaris,comp.unix.shell
#From: gwc@root.co.uk (Geoff Clare)
#Subject: Re: timeout -t <sec> <unix command> (Re: How to give rsh a shorter timeout?)
#Message-ID: <EoBxrs.223@root.co.uk>
#Date: Fri, 13 Feb 1998 18:23:52 GMT
#
# Conversion to bash v2 syntax done by Chet Ramey <chet@po.cwru.edu
# UNTESTED
#
prog=${0##*/}
usage="usage: $prog [-signal] [timeout] [:interval] [+delay] [--] <command>"
SIG=-TERM # default signal sent to the process when the timer expires
timeout=60 # default timeout
interval=15 # default interval between checks if the process is still alive
delay=2 # default delay between posting the given signal and
# destroying the process (kill -KILL)
while :
do
case $1 in
--) shift; break ;;
-*) SIG=$1 ;;
[0-9]*) timeout=$1 ;;
:*) EXPR='..\(.*\)' ; interval=`expr x"$1" : "$EXPR"` ;;
+*) EXPR='..\(.*\)' ; delay=`expr x"$1" : "$EXPR"` ;;
*) break ;;
esac
shift
done
case $# in
0) echo "$prog: $usage" >&2 ; exit 2 ;;
esac
(
for t in $timeout $delay
do
while (( $t > $interval ))
do
sleep $interval
kill -0 $$ || exit
t=$(( $t - $interval ))
done
sleep $t
kill $SIG $$ && kill -0 $$ || exit
SIG=-KILL
done
) 2> /dev/null &
exec "$@"
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