Replace 'which' with 'command -v' to test for the existance of an executable

This is considered to be more robust.

Two instances remain:

scripts/build/chroot_archives, line 257:
if [ "${LB_APT}" = "aptitude" ] && [ ! $(Chroot chroot "which aptitude") ]
The command is run inside a chroot where the environment might be special,
and would need further testing.

manpages/Makefile, line 42:
@if [ ! -x "$$(which po4a 2>/dev/null)" ]; \
I am insufficiently familiar with makefile syntax to edit this.

1 files changed, 1 insertions, 1 deletions

diff --git a/share/bin/Packages b/share/bin/Packages
index ad69fad83..60cd999fc 100755
--- a/share/bin/Packages
+++ b/share/bin/Packages
@@ -11,7 +11,7 @@
 
 set -e
 
-if [ ! $(which grep-aptavail) ]
+if ! command -v grep-aptavail >/dev/null
 then
 	echo "E: program grep-aptavail not found!"